PHYS 2300 BYT1 Physics: Mechanics
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Free PHYS 2300 BYT1 Physics: Mechanics Questions
Mechanical Advantage is the
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number of times a machine increases the input force
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number of times a machine increases the input distance
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number of times a machine increases work input
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amount of input work lost to friction
Explanation
Explanation:The correct answer is "number of times a machine increases the input force." Mechanical advantage (MA) is a measure of how effectively a machine amplifies the input force to perform work. It is calculated as the ratio of output force to input force. A higher mechanical advantage indicates that a smaller input force can move a larger load, making tasks easier. Mechanical advantage does not refer to distance, work, or energy lost to friction.
Correct Answer:
number of times a machine increases the input force
Why Other Options Are Wrong:
number of times a machine increases the input distance
This is incorrect because mechanical advantage specifically measures force amplification, not distance. While some machines trade distance for force, MA is defined by force ratios.
number of times a machine increases work input
This is wrong because machines cannot increase work; they can only redistribute force and distance. The work output is always equal to or less than the work input due to frictional losses.
amount of input work lost to friction
This is incorrect because mechanical advantage does not measure energy lost to friction. Friction affects efficiency, not the mechanical advantage itself.
Which of these is a second-class lever?
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Wheelbarrow
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Nutcracker
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Seesaw
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Both A & B
Explanation
Explanation:
The correct answer is "Both A & B." A second-class lever is characterized by having the load positioned between the fulcrum and the effort. Both a wheelbarrow and a nutcracker fit this description: in a wheelbarrow, the wheel acts as the fulcrum, the load is in the middle, and the person applies effort at the handles. In a nutcracker, the hinge is the fulcrum, the nut is the load in the middle, and effort is applied at the handles. This configuration allows a smaller effort to move a larger load efficiently.
Correct Answer:
Both A & B
Why Other Options Are Wrong:
Wheelbarrow
While a wheelbarrow is indeed a second-class lever, selecting only this option ignores the fact that a nutcracker is also a second-class lever, making the single-choice answer incomplete.
Nutcracker
A nutcracker alone is also a second-class lever, but the question asks for all second-class levers among the options. Only selecting this ignores the wheelbarrow, making it incomplete.
Seesaw
This is a Class 1 lever, where the fulcrum is between the effort and the load, so it does not qualify as a second-class lever.
The concept of mechanical advantage primarily relates to the efficiency of ___________ in amplifying force
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simple machines
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electrical circuits
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thermal energy
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chemical reactions
Explanation
Explanation:
The correct answer is "simple machines." Mechanical advantage measures how effectively a simple machine—such as a lever, pulley, wheel and axle, or inclined plane—can amplify an input force to accomplish work. It quantifies the ratio of output force to input force, reflecting the machine’s ability to make tasks easier. This concept is central to mechanics and engineering, as it allows a smaller force to move larger loads efficiently through the design of simple machines.
Correct Answer:
simple machines
Why Other Options Are Wrong:
electrical circuits
While electrical circuits can transform energy, the concept of mechanical advantage does not apply to them. Mechanical advantage specifically refers to force amplification in mechanical systems, not electrical systems.
thermal energy
Mechanical advantage does not relate to heat or energy transfer in thermal systems. Thermal energy deals with energy due to particle motion, not the ratio of forces in mechanical systems.
chemical reactions
Chemical reactions involve energy changes and transformations, but they do not amplify mechanical force through devices or systems, so mechanical advantage is not relevant in this context.
Which of the following statements accurately distinguishes between speed and velocity?
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Speed is a vector quantity, while velocity is a scalar quantity
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Velocity can change even if speed remains constant
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Speed is the total distance traveled divided by time, whereas velocity includes direction
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Velocity is always greater than speed
Explanation
Explanation:
The correct answer is "Speed is the total distance traveled divided by time, whereas velocity includes direction." Speed is a scalar quantity that measures how fast an object is moving regardless of direction. Velocity, on the other hand, is a vector quantity that specifies both magnitude and direction of motion. This distinction accurately separates the two concepts: speed considers only how much distance is covered over time, while velocity includes the direction of movement, making this the correct choice.
Correct Answer:
Speed is the total distance traveled divided by time, whereas velocity includes direction
Why Other Options Are Wrong:
Speed is a vector quantity, while velocity is a scalar quantity
This is incorrect because it reverses the definitions. Speed is a scalar, not a vector, and velocity is a vector quantity, so this statement misrepresents the fundamental properties of the two.
Velocity can change even if speed remains constant
While this statement is true in physics—for example, in uniform circular motion where speed is constant but direction changes—it does not directly distinguish speed from velocity. It describes a situation rather than defining the two concepts.
Velocity is always greater than speed
This is incorrect because the magnitude of velocity (speed) can never exceed the speed itself; in fact, the magnitude of velocity is equal to speed when direction is constant. The statement is logically false.
To maximize the distance a baseball travels after being hit, the player should aim to
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strike the ball with minimal force
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ensure the bat makes contact with the ball at an optimal angle
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swing the bat at a slower speed
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hit the ball with a flat trajectory
Explanation
Explanation:
To maximize the distance of a baseball hit, the optimal strategy is to strike the ball at an angle that maximizes projectile range, typically around 30–45 degrees relative to the ground. This allows the ball to achieve an ideal combination of vertical and horizontal motion. Contact at this optimal angle, combined with sufficient force and bat speed, ensures that the ball travels the greatest distance according to the principles of projectile motion in physics.
Correct Answer:
ensure the bat makes contact with the ball at an optimal angle
Why Other Options Are Wrong:
strike the ball with minimal force
This is incorrect because minimal force would not provide enough kinetic energy to the ball for maximum distance. Maximizing distance requires sufficient force, not minimal.
swing the bat at a slower speed
This is incorrect because a slower swing reduces the velocity imparted to the ball, decreasing the distance it travels. High bat speed contributes to greater kinetic energy transfer.
hit the ball with a flat trajectory
This is incorrect because a flat trajectory (close to horizontal) would reduce the time the ball stays in the air and limit distance. An optimal angle is necessary to balance height and horizontal range.
What is the vertical acceleration of a rock thrown straight upward on the way up? At the top of its flight? On the way down?
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Negative, Zero, Negative
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Positive, Zero, Negative
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Negative, Negative, Negative
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Negative, Zero, Positive
Explanation
Explanation:
Throughout the entire motion—going up, at the top, and coming down—the only vertical acceleration is due to gravity, which acts downward and is conventionally negative if upward is positive. It never becomes zero or positive.
Correct Answer:
Negative, Negative, Negative
Why Other Options Are Wrong:
Negative, Zero, Negative
This is incorrect because the vertical acceleration is not zero at the top; gravity continues to act downward.
Positive, Zero, Negative
This is wrong because the acceleration is never upward (positive) and never zero at the top.
Negative, Zero, Positive
This is incorrect because acceleration is never zero and never changes sign; it remains downward (negative) at all times.
A projectile is thrown directly upward and caught again. At the top of its path
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it stops accelerating
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its acceleration changes
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its horizontal velocity changes
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its vertical velocity is zero
Explanation
Explanation:
The correct answer is "its vertical velocity is zero." At the peak of its trajectory, the projectile momentarily stops moving vertically, so its vertical component of velocity is zero. However, the acceleration due to gravity remains constant and downward throughout the motion, so the projectile does not stop accelerating. For a vertically thrown projectile, there is no horizontal velocity to consider, so only the vertical velocity becomes zero at the top.
Correct Answer:
its vertical velocity is zero
Why Other Options Are Wrong:
it stops accelerating
This is incorrect because acceleration due to gravity acts downward continuously, even at the top of the path.
its acceleration changes
This is wrong because gravitational acceleration is constant in magnitude and direction near Earth’s surface.
its horizontal velocity changes
This is incorrect because for a purely vertical throw, there is no horizontal component of velocity; thus, it does not change.
What is pressure?
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same as force but expressed in different units
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force times the area over which the force acts
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force times the distance over which the force acts
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force divided by the area over which the force acts
Explanation
Explanation:
Pressure is defined as the amount of force applied per unit area. It quantifies how concentrated a force is over a surface and is a fundamental concept in fluid mechanics and physics. The correct mathematical representation of pressure is Pressure = Force ÷ Area, which means that for a given force, the pressure increases as the area over which the force is applied decreases. Pressure is not simply a force in different units, nor is it the product of force and area or force and distance.
Correct Answer:
force divided by the area over which the force acts
Why Other Options Are Wrong:
same as force but expressed in different units
This is incorrect because pressure and force are distinct physical quantities. Pressure depends on both the force and the area over which it is applied, not just a unit conversion of force.
force times the area over which the force acts
This is incorrect because multiplying force by area gives a different physical quantity, not pressure. Pressure decreases as the area increases for the same force, which contradicts this formula.
force times the distance over which the force acts
This is incorrect because multiplying force by distance calculates work, not pressure. Pressure is independent of distance and only relates to force and area.
Which of the following is the correct formula for torque?
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T=F/r
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T=rF
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T=ma
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T=Iw
Explanation
Explanation:
The correct answer is "T=rF." Torque is defined as the rotational equivalent of force, representing the tendency of a force to cause an object to rotate about an axis. The magnitude of torque is calculated as the product of the force applied and the perpendicular distance (moment arm) from the axis of rotation to the line of action of the force. Therefore, the formula T = rF correctly expresses this relationship, where T is torque, r is the moment arm, and F is the applied force.
Correct Answer:
T=rF
Why Other Options Are Wrong:
T=F/r
This is incorrect because torque is not calculated by dividing force by distance. Doing so would incorrectly reduce the effect of force on rotation instead of scaling it proportionally with the moment arm.
T=ma
This formula represents Newton’s second law for linear motion, where force equals mass times acceleration, not torque. It does not relate to rotational effects.
T=Iw
This formula is used to describe rotational inertia and angular momentum (torque in relation to rotational acceleration) but is not the general definition of torque. It applies only in specific dynamics contexts, not the basic torque formula.
An object is in a free fall under the Earth's gravitational acceleration. How far does it fall in 20 seconds? Use the equation for distance when acceleration is present: d = 1/2 g t2
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500 meters
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4000 meters
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25 meters
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2000 meters
Explanation
Explanation:
For an object in free fall, the distance fallen under constant gravitational acceleration can be calculated using the formula:
d = ½ g t²
where g = 9.8 m/s² (approximate value of gravitational acceleration) and t is the time in seconds. Substituting t = 20 s:
d = ½ × 9.8 × (20)² = 0.5 × 9.8 × 400 = 4.9 × 400 = 1960 m
Rounding to the closest option gives approximately 2000 meters.
Correct Answer:
2000 meters
Why Other Options Are Wrong:
500 meters
This is incorrect because it significantly underestimates the distance fallen over 20 seconds of free fall under gravity.
4000 meters
This is incorrect because it overestimates the distance. Doubling the correct calculation leads to 4000 m, which is not accurate.
25 meters
This is incorrect because it represents a very small fraction of the distance an object would fall over 20 seconds.
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