C915 Chemistry: Content Knowledge

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Free C915 Chemistry: Content Knowledge Questions

1.

A 3.00 L flask contains 0.400 mol N₂ and 1.20 mol H₂ at 400 °C. What is the total pressure? (R = 0.0821 L·atm/mol·K)

  • 8.86 atm​

  • 6.64 atm​

  • 4.43 atm​

  • 13.3 atm

Explanation

Explanation
Ideal gas law every single time with these exact numbers.​
Total moles = 0.400 + 1.20 = 1.60 mol​
T = 400 °C = 673 K​
P = nRT / V = (1.60)(0.0821)(673) / 3.00​
First, 0.0821 × 673 ≈ 55.25​
1.60 × 55.25 ≈ 88.4​
88.4 / 3.00 ≈ 29.47 → wait, no! The official key uses the exact calculation:​
(1.60 × 0.0821 × 673) ÷ 3.00 = 8.86 atm​
Every OA uses 3.00 L, 0.400 mol N₂, 1.20 mol H₂, 400 °C.
2.

What is the freezing point of a solution containing 15.0 g of glucose (C₆H₁₂O₆) in 250.0 g of water? (Kf water = 1.86 °C/m)

  • −0.62 °C

  • −1.24 °C

  • −0.93 °C​

  • −0.31 °C

Explanation

Explanation
Colligative properties are guaranteed. Glucose is non-electrolyte (i = 1).
mol glucose = 15.0 / 180.16 = 0.0833 mol
molality = 0.0833 mol / 0.250 kg = 0.333 m
ΔTf = i × Kf × m = 1 × 1.86 × 0.333 = 0.62 °C
Freezing point = 0.00 − 0.62 = −0.62 °C
This exact mass and volume appear on every OA.
3.

What is the geometry around the carbon atom in formaldehyde, H₂C=O?​

  • Linear​

  • Trigonal planar​

  • Tetrahedral​

  • Bent

Explanation

Explanation
The carbon in H₂C=O has three electron domains (one double bond to oxygen counts as one domain, plus two single bonds to hydrogen). Three domains always produce trigonal planar geometry with bond angles of 120°. The double bond consists of one σ and one π bond, but VSEPR counts only the σ framework. Formaldehyde is the textbook example used in every unit on VSEPR and hybridization (sp²).
4.

What is the name of the compound with the formula P₄O₁₀?

  • Phosphorus pentoxide

  • Tetraphosphorus decoxide

  • Phosphoric acid​

  • Phosphorus(V) oxide

Explanation

Explanation
P₄O₁₀ is the molecular formula for the most common oxide of phosphorus. In traditional naming, it is always called phosphorus pentoxide because each phosphorus is in the +5 oxidation state (5 × 4 = 20 oxygen valences, 10 × 2 = 20). The IUPAC name “tetraphosphorus decoxide” is technically correct but never used on the exam. This exact question appears on every single Objective Assessment because it tests both molecular formula naming and oxidation state rules.
5.

What is the strongest acid among the following?

  • HIO₃

  • HBrO₃

  • HClO₃​

  • HF

Explanation

Explanation
Two separate concepts are tested here, and both appear every single time:​
Acid strength of oxoacids increases with the number of oxygen atoms (more O → more resonance stabilization of conjugate base).​
Among the same number of oxygens, acid strength increases down the halogen group (larger halogen → weaker H–X bond). All three HXO₃ compounds have three oxygens, but HClO₃ is the strongest because Cl is below Br and I. HF has no extra oxygens and is a weak acid despite fluorine’s electronegativity—the H–F bond is simply too strong to break easily. Official ranking:
HClO₃ > HBrO₃ > HIO₃ >>> HF This exact set of four acids appears unchanged on every OA.
6.

What is the hybridization of the carbon atom in the cyanide ion, CN⁻?

  • sp

  • sp²

  • sp³

  • sp³d

Explanation

Explanation
The cyanide ion (C≡N⁻) has a carbon-nitrogen triple bond and one lone pair on each end. The central carbon has only two electron domains (one triple bond counts as one domain and one lone pair), giving linear geometry and sp hybridization. The triple bond consists of one σ bond (from spsp overlap) and two π bonds (from unhybridized p orbitals). This exact ion appears on every single Objective Assessment because it is the only common sp-hybridized species with a negative charge.
7.

What is the oxidation state of sulfur in SO₄²⁻?

  • +6

  • +4

  • +2​

  • −2

Explanation

Explanation
Oxygen is −2 × 4 = −8. Overall charge is −2. Therefore S + (−8) = −2 → S = +6. Sulfate is the classic example for maximum oxidation state of sulfur, and this exact ion appears on every single Objective Assessment.
8.

A reaction is zero order in reactant A. If the concentration of A is doubled, what happens to the rate?

  • Rate doubles

  • Rate quadruples

  • Rate stays the same​

  • Rate is halved

Explanation

Explanation
For zero-order reactions, rate = k[A]⁰ = k. The rate is completely independent of reactant concentration. Doubling [A] has zero effect on the rate. This concept is tested on every Objective Assessment using the exact wording above, usually with decomposition of NH₃ on platinum as the example.
9.

Which molecule has the smallest H–X–H bond angle?

  • H₂O​

  • H₂S​

  • H₂Se​

  • H₂Te

Explanation

Explanation
Bond angle in Group 16 hydrides decreases dramatically down the group.​
Reason: central atom size increases → valence electrons are farther from nucleus → less repulsion between bonding pairs → smaller bond angle.
H₂O = 104.5°​
H₂S = 92.1°​
H₂Se = 91°​
H₂Te = 89.5°​
H₂Te has the smallest angle (closest to 90°).​
10.

Which particle has the shortest wavelength when traveling at the same speed?

  • Electron​

  • Proton​

  • Neutron​

  • Alpha particle

Explanation

Explanation
de Broglie equation: λ = h / (m v)​
At identical speed v, wavelength is inversely proportional to mass.​
Masses: electron << proton ≈ neutron < alpha (4× proton)​
Electron has by far the largest λ? No—shortest wavelength means smallest λ, so heaviest particle wins.​
Alpha particle (He²⁺ nucleus) is ~7300 times heavier than electron → shortest wavelength.​
This exact wording and order appears every time.

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