P1 OSCE Calculations Exam at Chicago State University School of Pharmacy
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Free P1 OSCE Calculations Exam at Chicago State University School of Pharmacy Questions
Syrup is an 85% w/v solution of sucrose in water. It has a density of 1.313 g/mL.
How many milliliters of water should be used to make 300 mL of syrup?
Round to the nearest tenth. Do not include units.
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A 120.5
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B 138.9
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C 150.0
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D 165.2
Explanation
Explanation
To find the amount of water needed, first determine the total mass of 300 mL of syrup:300 mL × 1.313 g/mL = 393.9 g.
An 85% w/v syrup contains 85 g sucrose per 100 mL, so for 300 mL:
85 g × 3 = 255 g sucrose.
Subtract sucrose mass from total mass to find water mass:
393.9 g − 255 g = 138.9 g water.
Because water has a density of 1 g/mL, this equals 138.9 mL.
Correct Answer Is:
B. 138.9A patient weighing 165 lb is prescribed daptomycin 6 mg/kg IV once daily. The pharmacy has daptomycin 500 mg as a sterile powder, and the reconstitution instructions on the label say to add 10 mL of 0.9% sodium chloride (NS) to the vial to create a reconstituted solution containing daptomycin 50 mg/mL. How many milliliters of reconstituted drug need to be withdrawn from the vial to create the prescribed dose? Round answer to the nearest whole number. Do not include units.
Explanation
Correct Answer: 9
Step 1: Convert weight: 165 ÷ 2.2 = 75 kg
Step 2: Calculate dose: 75 kg × 6 mg/kg = 450 mg
Step 3: Calculate volume: 450 mg ÷ 50 mg/mL = 9 mL ✓
A prescription calls for 50 milligrams of chlorpheniramine maleate. Using a prescription balance with a sensitivity requirement of 6 milligrams, explain how you would obtain the required amount of chlorpheniramine maleate with an error not greater than 5%.
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A Weigh 600 mg chlorpheniramine maleate, dilute with 850 mg of diluent to make 1600 mg, then weigh 1200 mg
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B Weigh 150 mg chlorpheniramine maleate, dilute with 450 mg of diluent to make 600 mg, then weigh 200 mg
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C Weigh 60 mg chlorpheniramine maleate, dilute with 50 mg of diluent to make 100 mg, then weigh 20 mg
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D Weigh 760 mg chlorpheniramine maleate, dilute with 950 mg of diluent to make 6000 mg, then weigh 2000 mg
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E Weigh 120 mg chlorpheniramine maleate, dilute with 780 mg of diluent to make 1000 mg, then weigh 200 mg
Explanation
Explanation
With a sensitivity requirement of 6 mg and a maximum error of 5%, the minimum quantity that can be weighed accurately is (SR × 100) / %error = (6 × 100) / 5 = 120 mg. So both the initial drug weight and the final aliquot must be ≥ 120 mg. In option B, 150 mg drug (≥120 mg) is mixed with 450 mg diluent to make 600 mg total. The concentration is 150/600 = 0.25 (25%). Taking a 200 mg aliquot (also ≥120 mg) gives 0.25 × 200 = 50 mg of chlorpheniramine maleate, meeting the dose requirement while satisfying the balance’s accuracy limits.Correct Answer Is:
B. Weigh 150 mg chlorpheniramine maleate, dilute with 450 mg of diluent to make 600 mg, then weigh 200 mgWhat is the concentration, in ratio strength, of a trituration made by combining 100 mg of ibuprofen and 2.5 grams of talcum powder? Use the format 1:XX
Explanation
Correct Answer: 1:26
Total mixture = 100 mg + 2,500 mg = 2,600 mg 100 mg / 2,600 mg = 1/26 Ratio strength = 1:26
A solution contains 0.4% w/v of active ingredient.
How many kilograms of active ingredient are needed to prepare 800 L of solution?
Round answer to the nearest tenth. Do not include units.
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A 1.6
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B 2.4
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C 3.2
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D 4.0
Explanation
Explanation
A 0.4% w/v solution contains 0.4 g per 100 mL.Convert 800 L to milliliters: 800 L = 800,000 mL.
Determine grams per milliliter: 0.4 g / 100 mL = 0.004 g/mL.
Multiply by total volume:
0.004 g/mL × 800,000 mL = 3200 g.
Convert to kilograms: 3200 g ÷ 1000 = 3.2 kg.
Correct Answer Is:
C. 3.2A metronidazole vaginal gel contains 0.75% of drug in 70-g tubes.
How many milligrams of drug will be contained in 10 g of application?
Round answer to the nearest whole number. Do not include units.
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A 50
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B 65
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C 75
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D 90
Explanation
Explanation
A 0.75% w/w preparation contains 0.75 g per 100 g of product.To determine how much drug is in 10 g:
0.75 g ÷ 100 g = 0.0075 g per gram.
0.0075 g × 10 g = 0.075 g, which equals 75 mg.
Therefore, 75 mg of metronidazole is contained in a 10-gram dose.
Correct Answer Is:
C. 75How many milliequivalents of magnesium ion are present in each tablespoon of a 2% solution of magnesium sulfate (MW of MgSO4 is 120)? Round answer to the nearest whole number. Do not include units.
Explanation
Correct Answer: 5
Step 1: 1 tablespoon = 15 mL Step 2: Grams of MgSO4 in 15 mL of 2% solution: 15 mL × 0.02 = 0.3 g = 300 mg
Step 3: Milliequivalents of Mg²⁺ (valence = 2): mEq = (mg × valence) ÷ MW mEq = (300 × 2) ÷ 120 = 5 mEq ✓
A pharmacist adds 5.3 grams of hydrocortisone to 150 grams of 2.5% hydrocortisone ointment. What is the percentage strength (w/w) of hydrocortisone in the finished product? Round to the nearest whole number. Do not include the percent sign.
Explanation
Correct Answer: 5
Step 1: Find grams of hydrocortisone already in the 150g ointment: 150 g × 2.5% = 3.75 g
Step 2: Add the additional hydrocortisone: 3.75 g + 5.3 g = 9.05 g
Step 3: Calculate new total weight: 150 g + 5.3 g = 155.3 g
Step 4: Calculate new percentage strength: 9.05 g ÷ 155.3 g × 100 = 5.8% ≈ 6%
Correction upon rounding: 5.82% rounds to 6 ✓
The pharmacist is tasked with making an elixir that is 1:2000 (w/v) of phenobarbital. The pharmacy has 300 mL of a 0.5% elixir to be used for this. How many milliliters of the 1:2000 (w/v) elixir can be made? (Round to the nearest whole number. Do not include units.)
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A 1500
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B 2000
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C 2500
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D 3000
Explanation
Explanation
A 0.5% w/v phenobarbital elixir contains 0.5 g per 100 mL, which is 500 mg per 100 mL, or 5 mg/mL.With 300 mL available:
5 mg/mL × 300 mL = 1500 mg total drug.
A 1:2000 solution contains 1 g in 2000 mL, or 0.5 mg/mL.
To find the final volume that will contain 1500 mg at a concentration of 0.5 mg/mL:
1500 mg ÷ 0.5 mg/mL = 3000 mL. Therefore, 3000 mL of the 1:2000 elixir can be prepared.
Correct Answer Is:
D. 3000A prescription calls for 5 mg of morphine sulfate. Using a sensitivity requirement of 5 mg, how would you obtain the required amount of morphine sulfate with an error not greater than 5%?
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A 125 mg of drug, 1675 mg of diluent, 80 mg of aliquot
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B 80 mg of drug, 1920 mg of diluent, 80 mg of aliquot
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C 100 mg of drug, 1900 mg of diluent, 100 mg of aliquot
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D 120 mg of drug, 2000 mg of diluent, 100 mg of aliquot
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E 150 mg of drug, 2250 mg of diluent, 100 mg of aliquot
Explanation
Explanation
With a sensitivity requirement (SR) of 5 mg and a maximum error of 5%, the minimum quantity that can be weighed accurately is: (SR × 100) / % error = (5 × 100) / 5 = 100 mg. Therefore, the aliquot taken must be at least 100 mg. In option C, 100 mg drug + 1900 mg diluent = 2000 mg mixture. A 100 mg aliquot of this mixture contains (100/2000) × 100 mg = 5 mg morphine sulfate, meeting both the dose requirement and the weighing accuracy requirement.Correct Answer Is:
C. 100 mg of drug, 1900 mg of diluent, 100 mg of aliquotHow to Order
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