C832 Chemistry with Lab

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Free C832 Chemistry with Lab Questions

1.

Which compound has only single bonds in its Lewis structure?

  • C₂H₄

  • C₂H₆

  • C₂H₂

  • CO₂

Explanation

Explanation:
C₂H₆, known as ethane, contains only single covalent bonds between the atoms. Each carbon forms four single bonds—three with hydrogen atoms and one with the other carbon atom. In contrast, C₂H₄ (ethylene) has a double bond, C₂H₂ (acetylene) has a triple bond, and CO₂ contains double bonds between carbon and oxygen atoms. Therefore, C₂H₆ is the only compound listed that consists entirely of single bonds.
Correct Answer: C₂H₆

Why the other options are incorrect:
C₂H₄ has C=C double bond; C₂H₂ has C≡C triple bond; CO₂ has C=O double bonds.
2.

What is the coefficient of H₂O when the equation __Fe + __H₂O → Fe₃O₄ + __H₂ is balanced?

  • 2

  • 3

  • 4

  • 8

Explanation

To balance the reaction Fe + H₂O → Fe₃O₄ + H₂, start by balancing iron (Fe). Since there are 3 Fe atoms in Fe₃O₄, place a coefficient of 3 before Fe. To balance the oxygen and hydrogen atoms, 4 H₂O molecules are needed to provide 4 oxygen atoms. This results in the formation of 4 H₂ molecules to balance hydrogen. The balanced equation is 3Fe + 4H₂O → Fe₃O₄ + 4H₂.
Correct Answer: 4
3.

Name the compound Pb(SO₄)₂.

  • Lead(II) sulfate

  • Lead(IV) sulfate

  • Lead bisulfate

  • Lead sulfide

Explanation

Explanation:
The correct name for Pb(SO₄)₂ is lead(IV) sulfate. Each sulfate ion (SO₄²⁻) carries a -2 charge, and since there are two sulfate ions, the total negative charge is -4. To balance this, lead must have a +4 charge, hence the Roman numeral (IV). This naming follows the rules for ionic compounds with metals that can have multiple oxidation states.
Correct Answer: Lead(IV) sulfate
4.

A student cuts his hand on a broken beaker, resulting in significant bleeding. What should you do?

  • Make sure the student is safe and call on a medical professional to provide treatment.

  • Have the student continue working to avoid disrupting the experiment.

  • Rinse the wound quickly and cover it with a dirty cloth.

  • Ignore the cut if the bleeding slows down on its own.

Explanation

Explanation:
When a student sustains a significant cut in the laboratory, the priority is to ensure their safety and seek medical assistance immediately. The student should be moved away from the work area, and any active bleeding should be controlled using clean gauze or a sterile dressing while waiting for medical help.
Why the other options are incorrect:
Continuing work, ignoring the injury, or using unclean materials can lead to infection and worsen the condition. Prompt medical attention ensures the wound is properly treated and contamination risks are minimized.
5.

Resonance structures are required for which molecule?

  • CH₄

  • CO₂

  • O₃

  • BF₃

Explanation

Resonance occurs when more than one valid Lewis structure can be drawn for a molecule, differing only in the placement of electrons, not atoms. Ozone (O₃) exhibits resonance because the arrangement of single and double bonds between the three oxygen atoms can alternate, leading to two equivalent structures. This delocalization of electrons stabilizes the molecule.
Correct Answer: O₃
6.

There are three p orbitals that are aligned with their major axes along the x, y, and z axes. What is the origin of these three p orbitals?

  • They are the solutions for the three values of the magnetic quantum number.

  • They arise from the three possible values of the principal quantum number.

  • They come from the three possible spin orientations of an electron.

  • They are determined by the three possible energy levels of p orbitals.

Explanation

Explanation:
The three p orbitals (px, py, pz) originate from the three possible values of the magnetic quantum number (mₗ) when the angular quantum number (l) equals 1. For p orbitals, l = 1, and mₗ can take values of −1, 0, and +1. Each value corresponds to a different spatial orientation of the orbital along one of the three axes (x, y, and z). These orbitals are equal in energy (degenerate) in a free atom but can vary slightly when external fields or bonding interactions are present.

Correct Answer:
They are the solutions for the three values of the magnetic quantum number.
7.

In 2H₂ + O₂ → 2H₂O, how many liters of O₂ at STP are needed for 44.8 L of H₂?

8.

Which molecule exhibits sp² hybridization on the central atom?

  • CH₄

  • SO₃

  • PF₅

  • SF₆

Explanation

Explanation:
SO₃ (sulfur trioxide) has a central sulfur atom bonded to three oxygen atoms with no lone pairs. The sulfur atom forms three sigma bonds and uses three hybrid orbitals, which corresponds to sp² hybridization. This allows for a trigonal planar geometry with bond angles of approximately 120°.
Why the other options are incorrect:
In contrast, CH₄ is sp³, PF₅ is sp³d, and SF₆ is sp³d² hybridized.
Correct Answer: SO₃
9.

Which electron configuration correctly represents an atom of nickel?

  • 1s²2s²2p⁶3s²3p⁶4s²3d⁸

  • 1s²2s²2p⁶3s²3p⁶3d¹⁰

  • 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰

  • 1s²2s²2p⁶3s²3p⁶3d⁸

Explanation

Explanation:
Nickel has an atomic number of 28, so it contains 28 electrons. Following the order of orbital filling, its correct electron configuration is 1s²2s²2p⁶3s²3p⁶4s²3d⁸. The 4s orbital fills before the 3d orbital, even though 3d has a higher energy level.
Why the other options are incorrect:
Some of the other options either omit the 4s electrons or have incorrect total electron counts.
10.

What volume of O₂ is required to react completely with 44.8 L of H₂ at STP?

  • 22.4 L

  • 44.8 L

  • 89.6 L

  • 11.2 L

Explanation

Explanation:
The balanced equation shows that 2 moles of H₂ react with 1 mole of O₂ to form 2 moles of H₂O. Using the volume ratio at STP (where 1 mole of gas occupies 22.4 L), 44.8 L of H₂ is equivalent to 2 moles. According to the 2:1 stoichiometric ratio, 1 mole of O₂ (22.4 L) is needed to react completely with 2 moles (44.8 L) of H₂.
Correct Answer: 22.4 L

Why the other options are incorrect:
44.8 L would correspond to 2 moles of O₂, which is twice the required amount based on the 2:1 ratio.
89.6 L is four times the required volume, not matching the stoichiometry.
11.2 L is half the required amount, which would not fully react with 44.8 L of H₂.

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