ITSW 3173 D287 Java Frameworks
Access The Exact Questions for ITSW 3173 D287 Java Frameworks
💯 100% Pass Rate guaranteed
🗓️ Unlock for 1 Month
Rated 4.8/5 from over 1000+ reviews
- Unlimited Exact Practice Test Questions
- Trusted By 200 Million Students and Professors
What’s Included:
- Unlock Actual Exam Questions and Answers for ITSW 3173 D287 Java Frameworks on monthly basis
- Well-structured questions covering all topics, accompanied by organized images.
- Learn from mistakes with detailed answer explanations.
- Easy To understand explanations for all students.
Free ITSW 3173 D287 Java Frameworks Questions
Which of the following best describes the primary characteristic of a List in the Java Collections Framework?
-
A collection that allows for unique elements only
-
A collection that stores elements in a random order
-
A collection that maintains the order of elements based on their insertion
-
A collection that maps keys to values
Explanation
Correct Answer
C. A collection that maintains the order of elements based on their insertion
Explanation
In the Java Collections Framework, a List is an ordered collection that maintains the order of elements based on their insertion. This means that elements in a List are stored in the order they are added, and their positions can be indexed (e.g., using the get() method). The List interface allows for duplicate elements, unlike sets, and provides a way to store elements in a predictable sequence.
Why other options are wrong
A. A collection that allows for unique elements only
This is incorrect because a List allows duplicate elements. Unlike a Set, which only allows unique elements, a List can store multiple occurrences of the same element.
B. A collection that stores elements in a random order
This is incorrect because a List maintains the order of elements based on their insertion, not in a random order. The order of elements is predictable, and each element has a specific index position.
D. A collection that maps keys to values
This is incorrect because a collection that maps keys to values is a Map, not a List. A Map stores key-value pairs, where each key is unique and associated with a value. A List does not have this functionality.
What is a "Map"?
-
A collection of key/value pairs in which each key is associated with a corresponding value
-
An ordered collection of elements, often accessed by integer indexes or by iteration
-
A collection in which elements are removed in the same order in which they were added
-
A collection of integers that are associated with an array of the corresponding value
Explanation
Correct Answer
A. A collection of key/value pairs in which each key is associated with a corresponding value
Explanation
In Java, a Map is a part of the Collections Framework used to store data in the form of key-value pairs. Each key in a Map must be unique, and each key maps to exactly one value. This allows for efficient retrieval and updating of values based on their associated keys.
Why other options are wrong
B. An ordered collection of elements, often accessed by integer indexes or by iteration
This is incorrect because it describes a List, not a Map. Lists, such as ArrayList or LinkedList, maintain insertion order and allow indexed access, which is not how a Map functions.
C. A collection in which elements are removed in the same order in which they were added
This describes a queue-like structure, specifically a FIFO (First-In-First-Out) data structure such as Queue or LinkedList. It does not reflect how a Map operates, where ordering (if any) depends on the implementation and elements are accessed by key, not by order of insertion.
D. A collection of integers that are associated with an array of the corresponding value
This is incorrect because it is not a proper definition of a Map in Java. A Map can have any object type as keys and values—not just integers or arrays. This option also confuses arrays with key-value mappings, which are entirely different structures.
In the Java Collections Framework, what is the main job of a Map?
-
To store elements in a sorted order
-
To maintain a collection of unique elements
-
To associate keys with values
-
To allow duplicate entries
Explanation
Correct Answer
C. To associate keys with values
Explanation
The Map interface in Java is designed to store key-value pairs, where each key is associated with exactly one value. It enables efficient retrieval, insertion, and deletion of elements based on the key. This makes Map ideal for scenarios requiring quick access to data using identifiers, like lookup tables.
Why other options are wrong
A. To store elements in a sorted order
This is incorrect because sorting is not the primary function of a Map. While some implementations like TreeMap do store entries in a sorted order based on keys, the core purpose of the Map interface is to associate keys with values, not to maintain order.
B. To maintain a collection of unique elements
This is incorrect because the Set interface is specifically designed for maintaining a collection of unique elements. In a Map, uniqueness is enforced only on keys, not on values. Duplicate values are allowed, so this option does not accurately describe a Map.
D. To allow duplicate entries
This is incorrect because Map does not allow duplicate keys. Although it allows duplicate values, the uniqueness of keys is a fundamental characteristic of Map. This option could be misleading and doesn't describe the primary function of a Map.
What is a basic principle to keep in mind when working with lists?
-
lists will grow and shrink as needed
-
a list is a sequence of items stored as a single object
-
lists support many convenient and frequently used methods
-
items in a list can be accessed by indexing
-
all of the above
Explanation
Correct Answer
E. all of the above
Explanation
All of the listed statements are accurate characteristics of lists in programming. Lists are dynamic structures, meaning they can grow and shrink as needed. They hold sequences of items in a single object, making them ideal for managing collections of data. Lists also offer many useful methods like append(), remove(), and sort() that make them versatile. Access to individual elements is made easy through indexing, which allows direct access by position.
Why other options are wrong
A. lists will grow and shrink as needed
This statement is true, but it only covers one aspect of list functionality. It fails to reflect the full scope of what lists offer, such as their method support and indexing capabilities.
B. a list is a sequence of items stored as a single object
This is accurate, but it is not the complete answer. It doesn't consider the list's dynamic size and available methods.
C. lists support many convenient and frequently used methods
Correct, but incomplete on its own. It omits the list’s capacity to grow dynamically, store items as a single object, and allow indexing.
D. items in a list can be accessed by indexing
This is true, but only one feature of lists. It overlooks the dynamic nature, method support, and sequence encapsulation.
In the Stack data structure, which method removes the top element?
-
pop()
-
isEmpty()
-
peek()
-
push()
Explanation
Correct Answer
A. pop()
Explanation
The pop() method is used in a stack to remove and return the top element. In a stack, this is the primary method for removing elements, adhering to the "last in, first out" (LIFO) principle.
Why other options are wrong
B. isEmpty()
This is incorrect because isEmpty() simply checks whether the stack is empty, but it does not remove any elements.
C. peek()
This is incorrect because peek() returns the top element of the stack without removing it. It allows you to view the top element but does not perform a removal.
D. push()
This is incorrect because push() adds an element to the top of the stack. It does not remove any elements.
The methods for modifying an element in the _________ class are synchronized.
-
ArrayList
-
LinkedList
-
Stack
-
Vector
Explanation
Correct Answer
D. Vector
Explanation
The Vector class in Java is synchronized, meaning that its methods for modifying elements (such as add(), remove(), and set()) are thread-safe. This ensures that only one thread can access and modify the vector at a time, which can be beneficial in multi-threaded environments. However, synchronization can lead to performance overhead compared to non-synchronized collections like ArrayList.
Why other options are wrong
A. ArrayList
This is incorrect because ArrayList is not synchronized. It is not thread-safe by default, so if multiple threads are accessing it concurrently, synchronization must be handled externally.
B. LinkedList
This is incorrect because LinkedList is also not synchronized. Like ArrayList, it is not thread-safe by default, and external synchronization is required if it is accessed by multiple threads.
C. Stack
This is incorrect because although Stack is part of the legacy collection classes, its methods are synchronized. However, Vector is the more commonly referenced synchronized collection in modern use. The distinction in the question specifically points to Vector as the synchronized collection.
Which of the following statements accurately describes the behavior of the Stack class methods push() and isEmpty()?
-
push() adds an element to the top of the stack, while isEmpty() checks if the stack has any elements.
-
push() removes the top element from the stack, while isEmpty() returns the top element.
-
push() retrieves the top element without removing it, while isEmpty() adds an element to the stack.
-
push() checks if the stack is full, while isEmpty() returns the number of elements in the stack.
Explanation
Correct Answer
A. push() adds an element to the top of the stack, while isEmpty() checks if the stack has any elements.
Explanation
The push() method adds an element to the top of the stack, which is the primary function of the stack data structure. The isEmpty() method checks whether the stack is empty, returning true if there are no elements and false if the stack contains elements.
Why other options are wrong
B. push() removes the top element from the stack, while isEmpty() returns the top element.
This is incorrect because push() does not remove elements; it only adds elements to the top of the stack. The method for removing elements is pop(), not push(). Also, isEmpty() does not return the top element; it only checks if the stack is empty.
C. push() retrieves the top element without removing it, while isEmpty() adds an element to the stack.
This is incorrect because push() adds an element to the stack, not retrieves it. The method for retrieving the top element without removing it is peek(). Additionally, isEmpty() checks if the stack is empty; it does not add elements.
D. push() checks if the stack is full, while isEmpty() returns the number of elements in the stack.
This is incorrect because push() does not check if the stack is full. It adds elements to the stack, and isEmpty() only checks whether the stack is empty, not the number of elements in it.
What constructor parameters are required to create a LinkedHashMap that maintains access order?
-
LinkedHashMap(int initialCapacity, float loadFactor, boolean accessOrder)
-
LinkedHashMap(int initialCapacity)
-
LinkedHashMap()
-
LinkedHashMap(float loadFactor, boolean accessOrder)
Explanation
Correct Answer
A. LinkedHashMap(int initialCapacity, float loadFactor, boolean accessOrder)
Explanation
To create a LinkedHashMap that maintains access order (meaning it reorders entries based on access, not just insertion), you must use the constructor with all three parameters: initial capacity, load factor, and a boolean flag for access order. When accessOrder is set to true, the map maintains access order rather than insertion order.
Why other options are wrong
B. LinkedHashMap(int initialCapacity)
This constructor allows setting only the initial capacity of the map. It does not offer control over access order, so the map will use the default (insertion order), not access order.
C. LinkedHashMap()
This no-argument constructor creates a LinkedHashMap with default capacity and load factor, and it maintains insertion order by default. It does not allow you to specify access order, which is essential for the behavior asked in the question.
D. LinkedHashMap(float loadFactor, boolean accessOrder)
This is incorrect because there is no such constructor in the LinkedHashMap class that takes only a float and a boolean as parameters. To specify access order, you must also provide the initial capacity.
What is the purpose of the "peek" method in a Stack?
-
To return a reference to the top element of the stack, and remove it from the stack.
-
To return a reference to the bottom element of the stack, but leave it in place.
-
To return a reference to the top element of the stack, but leave it in place.
-
To return a reference to the top element of the stack, and move it to the bottom of the stack.
Explanation
Correct Answer
C. To return a reference to the top element of the stack, but leave it in place.
Explanation
The peek method in a stack returns a reference to the top element of the stack without removing it. It allows you to look at the element at the top of the stack without modifying the stack. This is useful when you need to examine the top item but not alter the structure of the stack.
Why other options are wrong
A. To return a reference to the top element of the stack, and remove it from the stack.
This is incorrect because it describes the behavior of the pop method, not peek. The pop method removes and returns the top element, while peek only returns the top element without removing it.
B. To return a reference to the bottom element of the stack, but leave it in place.
This is incorrect because a stack operates on the LIFO (Last In, First Out) principle, meaning only the top element is accessible directly, not the bottom. The peek method accesses the top element, not the bottom.
D. To return a reference to the top element of the stack, and move it to the bottom of the stack.
This is incorrect because the peek method does not modify the stack; it only returns the top element without changing the stack's order. Moving the element to the bottom would be a different operation.
An application can indicate a specific way to order the elements of a SortedABList list by passing this type of object to a constructor of the list class:
-
Iterator
-
Iterable
-
Comparator
-
Comparable
-
None of these is correct
Explanation
Correct Answer
C. Comparator
Explanation
When creating a sorted list, such as a SortedABList, an application can provide a Comparator to define how the elements should be ordered. The Comparator allows the user to specify a custom order, different from the natural ordering (which is defined by the Comparable interface). This gives greater flexibility when sorting elements, especially if the elements do not implement Comparable or if a different sorting order is desired.
Why other options are wrong
A. Iterator
An Iterator is used to iterate over the elements of a collection, but it does not define any ordering of the elements. It simply allows traversal.
B. Iterable
An Iterable defines the ability to iterate over a collection, but it does not specify how the elements should be ordered. The ordering of elements is handled by the collection's implementation (e.g., using a Comparator or Comparable).
D. Comparable
The Comparable interface defines the natural ordering of elements within a class, but it does not allow for custom sorting. It is a mechanism for elements that can compare themselves. A Comparator is used when a custom order is needed.
E. None of these is correct
This is incorrect because the Comparator is the correct answer for passing a custom order to the constructor of a SortedABList.
How to Order
Select Your Exam
Click on your desired exam to open its dedicated page with resources like practice questions, flashcards, and study guides.Choose what to focus on, Your selected exam is saved for quick access Once you log in.
Subscribe
Hit the Subscribe button on the platform. With your subscription, you will enjoy unlimited access to all practice questions and resources for a full 1-month period. After the month has elapsed, you can choose to resubscribe to continue benefiting from our comprehensive exam preparation tools and resources.
Pay and unlock the practice Questions
Once your payment is processed, you’ll immediately unlock access to all practice questions tailored to your selected exam for 1 month .