Java Fundamentals (D286)

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Free Java Fundamentals (D286) Questions
Where should instance variables be declared in Java?
-
Inside a class and inside a constructor
-
Inside a class but outside a constructor
-
Inside a method
-
Inside a constructor
Explanation
Correct Answer
B. Inside a class but outside a constructor
Explanation
Instance variables in Java are declared inside a class but outside of any methods or constructors. These variables represent the state of an object and are associated with the instance of the class. Declaring them outside the constructor ensures that they are accessible throughout the instance of the class and can hold different values for each object. Constructors, on the other hand, are used to initialize these instance variables, but the variables themselves are not declared within them.
Why other options are wrong
A. Inside a class and inside a constructor
This is incorrect because instance variables should not be declared inside the constructor. The constructor is used to initialize the instance variables, not declare them.
C. Inside a method
This is incorrect because instance variables are not declared inside methods. If declared inside a method, they would be considered local variables, not instance variables, and would only be accessible within that method.
D. Inside a constructor
This is incorrect because instance variables are declared at the class level, not within the constructor. Constructors are responsible for initializing the variables, not declaring them.
In a program, a literal is a value that is:
-
Calculated by the computer
-
Typed into the source code by the programmer
-
Both of the above
-
None of the above
Explanation
Correct Answer
B. Typed into the source code by the programmer
Explanation
A literal in programming is a fixed value explicitly written in the source code by the programmer. For example, 100, "Hello", and 'A' are all literals in Java. They represent specific values that are hard-coded into the program and are not calculated by the computer.
Why other options are wrong
A. Calculated by the computer
This is incorrect. A literal is a direct value given in the code, not something computed during program execution. For example, 100 in the code is a literal, but the result of an expression like 2 + 2 is not a literal; it's computed at runtime.
C. Both of the above
This is incorrect. Only the value typed into the source code is considered a literal, not something calculated by the computer. So, this option is not accurate.
D. None of the above
This is incorrect because option B is correct. A literal is indeed typed into the source code by the programmer.
What is the correct way to update the value of an existing variable in Java?
-
Use the increment operator '++'
-
Reassign it with the assignment operator '='
-
Declare a new variable with the same name
-
Use the addition operator '+' directly
Explanation
Correct Answer
B. Reassign it with the assignment operator '='
Explanation
In Java, the assignment operator (=) is used to update the value of an existing variable. This operator allows a variable to hold a new value, overwriting the previous one. For example, if x was previously assigned the value 5, you can update it to 10 by writing x = 10;.
Why other options are wrong
A. Use the increment operator '++'
This is incorrect because the increment operator ++ only increases the value of a variable by 1. While it does update the variable, it is not a general way to reassign any value to the variable.
C. Declare a new variable with the same name
This is incorrect because you cannot have two variables with the same name in the same scope. Declaring a new variable with the same name would cause a compilation error. Reassigning an existing variable is the correct approach.
D. Use the addition operator '+' directly
This is incorrect because the addition operator + performs addition on values, but it does not directly update a variable. For instance, you would need to use x = x + 1 to increment a variable's value, not just x + 1.
Which built-in class in Java provides the capability to read input from an input stream such as the keyboard?
-
System.in
-
Scanner
-
InputStream
-
Console
Explanation
Correct Answer
B. Scanner
Explanation
The Scanner class in Java is used to read input from various sources, including the keyboard (System.in). It provides methods like nextInt(), nextLine(), and next() to read different types of data from the input stream. For instance, Scanner scanner = new Scanner(System.in); is commonly used to read user input from the console.
Why other options are wrong
A. System.in
This is incorrect because System.in refers to the input stream itself (typically the keyboard in the case of console input), not a class that handles reading input. The Scanner class is used to read from this stream.
C. InputStream
This is incorrect because InputStream is a superclass for reading bytes from input sources, and although it can be used for reading data, it is not as convenient as the Scanner class for handling user input from the console.
D. Console
This is incorrect because the Console class is another way to read input, but it is less commonly used than Scanner. It also does not work well in certain environments, such as when running from an IDE or non-interactive contexts, making Scanner more widely used for input handling.
What is the default value assigned to a variable of the double data type in Java, and in what scenario is it advisable to avoid using this data type?
-
0.0; when dealing with precise calculations like currency
-
0; when performing integer arithmetic
-
null; when representing non-numeric data
-
1.0; when needing high precision in scientific calculations
Explanation
Correct Answer
A. 0.0; when dealing with precise calculations like currency
Explanation
In Java, the default value of a double variable is 0.0. However, it is advisable to avoid using double when dealing with precise calculations, such as currency, due to the potential for rounding errors. For accurate currency calculations, it is better to use BigDecimal.
Why other options are wrong
B. 0; when performing integer arithmetic
This is incorrect because the default value of a double is 0.0, not 0. Moreover, double is not typically used for integer arithmetic, which is better handled by int or long.
C. null; when representing non-numeric data
This is incorrect because null is not the default value of a double in Java. null can only be assigned to object references, not primitive types like double.
D. 1.0; when needing high precision in scientific calculations
This is incorrect because the default value of a double is 0.0, not 1.0. Also, while double can be used for scientific calculations, its lack of precision for certain tasks may lead to issues, especially in financial calculations, where BigDecimal is preferred.
From the statements below, pick one that is false.
-
The scope of a local variable is the portion of a method over which the variable is known and can be referenced.
-
Another name for a class method is a static method.
-
A variable of type char can be passed to a method that expects an int argument.
-
Primitive types used as method arguments are passed by reference.
Explanation
Correct Answer
D. Primitive types used as method arguments are passed by reference.
Explanation
In Java, primitive types (e.g., int, char, float) are passed by value, not by reference. This means that when a primitive type is passed as an argument to a method, the method gets a copy of the value, not the original variable. Changes made to the parameter inside the method do not affect the original variable.
Why other options are wrong
A. The scope of a local variable is the portion of a method over which the variable is known and can be referenced.
This is correct. The scope of a local variable is limited to the block of code (typically a method) in which it is declared. The variable can only be referenced within that block.
B. Another name for a class method is a static method.
This is correct. A method that belongs to the class, rather than an instance of the class, is referred to as a static method. It can be invoked using the class name and does not require an instance of the class.
C. A variable of type char can be passed to a method that expects an int argument.
This is correct. In Java, a char can be implicitly converted to an int, because a char is represented as a 16-bit Unicode value, which fits within an int. Java automatically converts a char to its corresponding integer value when passed to a method that expects an int.
Which of the following correctly describes a hexadecimal integer in Java?
-
A number represented in base 10 using digits 0-9
-
A number represented in base 16 using digits 0-9 and letters A-F, prefixed with 0x
-
A binary number represented using only 0s and 1s
-
A floating-point number represented in scientific notation
Explanation
Correct Answer
B. A number represented in base 16 using digits 0-9 and letters A-F, prefixed with 0x
Explanation
In Java, hexadecimal integers are represented in base 16. They use the digits 0-9 and the letters A-F, where A-F represent the values 10-15. Hexadecimal literals are prefixed with 0x or 0X. For example, 0x2F is a valid hexadecimal number in Java.
Why other options are wrong
A. A number represented in base 10 using digits 0-9
This is incorrect because base 10 is the standard decimal system, not hexadecimal. Hexadecimal is based on base 16, and base 10 uses only the digits 0-9.
C. A binary number represented using only 0s and 1s
This is incorrect because binary numbers are represented in base 2, not hexadecimal. Binary numbers are composed only of the digits 0 and 1, and in Java, they are prefixed with 0b or 0B, e.g., 0b101.
D. A floating-point number represented in scientific notation
This is incorrect because hexadecimal integers are not floating-point numbers, and they are not represented in scientific notation. Scientific notation is used for large or small floating-point numbers, not for integers.
What is the purpose of the Java compiler?
-
To transform Java code into instructions usable by the JVM
-
To transform Java code into instructions usable by the operating system
-
To transform Java code into instructions usable by a web browser
Explanation
Correct Answer
A. To transform Java code into instructions usable by the JVM
Explanation
The Java compiler (javac) compiles Java source code into bytecode, which is a platform-independent intermediate form of code. This bytecode can then be executed by the Java Virtual Machine (JVM). The JVM interprets or compiles this bytecode into machine code that the specific operating system can execute. The Java compiler does not generate executable machine code directly for an operating system, and it is not used for browser instructions.
Why other options are wrong
B. To transform Java code into instructions usable by the operating system
This is incorrect. The Java compiler transforms Java code into bytecode, not machine code for a specific operating system. The JVM is responsible for executing the bytecode on a particular platform.
C. To transform Java code into instructions usable by a web browser
This is incorrect. Java code is typically not executed directly in a web browser (except for applets, which are largely outdated). Web browsers generally run JavaScript, not Java bytecode. The JVM is used to run Java bytecode outside the browser, on the user's system.
What is the effect of applying the logical NOT operator ! to a boolean expression in Java?
-
It returns the original boolean value unchanged.
-
It converts the boolean value to an integer.
-
It inverts the boolean value, changing true to false and false to true.
-
It performs a bitwise negation on the boolean value.
Explanation
Correct Answer
C. It inverts the boolean value, changing true to false and false to true.
Explanation
The logical NOT operator ! in Java inverts the value of a boolean expression. If the expression is true, it becomes false, and if the expression is false, it becomes true. This operator is used to flip the value of a boolean in logical operations.
Why other options are wrong
A. It returns the original boolean value unchanged.
This is incorrect because the logical NOT operator explicitly inverts the boolean value, meaning the value is not left unchanged. It changes true to false and vice versa.
B. It converts the boolean value to an integer.
This is incorrect because the ! operator does not convert booleans to integers. It operates strictly on boolean values and simply inverts them, it does not perform any type conversion to integers.
D. It performs a bitwise negation on the boolean value.
This is incorrect because bitwise negation is a concept that applies to integer types (like int or long), and operates on the bits of the number. The logical NOT operator ! works solely with boolean values and does not involve bitwise operations.
You use ____ operators to perform calculations with values in your programs.
-
Calculation
-
Integer
-
Arithmetic
-
Precedence
Explanation
Correct Answer
C. Arithmetic
Explanation
Arithmetic operators are used in programming to perform basic mathematical operations such as addition, subtraction, multiplication, division, and modulus. These operators allow manipulation of numerical values within expressions and are fundamental in performing calculations in a program.
Why other options are wrong
A. Calculation
This is not a valid term for an operator type in programming. "Calculation" refers to the act or process of computing a result, not the operator used to do so. Thus, it is not the correct term in this context.
B. Integer
"Integer" refers to a data type, not an operator. Although arithmetic operators are often used with integers, the term itself is unrelated to the concept of performing calculations via operators.
D. Precedence
Operator precedence determines the order in which operations are performed in an expression but does not perform calculations itself. It is a rule that affects how expressions are evaluated, not a type of operator.
How to Order
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Java Fundamentals (D286) Study Notes
Table of Contents
-
Introduction to Java
- What is Java?
- Features of Java
- Java Development Kit (JDK) and Java Runtime Environment (JRE)
- Writing Your First Java Program
- Java Syntax and Data Types
- Variables and Data Types
- Operators
- Control Flow Statements (if-else, loops, switch)
- Object-Oriented Programming (OOP) in Java
- Classes and Objects
- Inheritance, Polymorphism, Encapsulation, and Abstraction
- Constructors and Methods
- Arrays and Strings
- Working with Arrays
- String Manipulation
- Exception Handling
- Types of Exceptions
- Try-Catch Blocks
- Custom Exceptions
- File Handling in Java
- Reading and Writing Files
- File Class Methods
- Case Study 1: Building a Student Management System
- Problem Statement
- Solution Design
- Code Implementation
- Analysis
- Case Study 2: Creating a Banking Application
- Problem Statement
- Solution Design
- Code Implementation
- Analysis
- Practice Questions and Answers
- 100 Q&A with Rationales
1. Introduction to Java
Java is a high-level, object-oriented programming language developed by Sun Microsystems (now owned by Oracle). It is platform-independent, meaning Java programs can run on any device with a Java Virtual Machine (JVM).
- Platform Independence: Write once, run anywhere (WORA).
- Object-Oriented: Everything in Java is an object.
- Secure: Built-in security features like bytecode verification.
- Multithreading: Supports concurrent execution of multiple threads.
- JDK: Used to develop Java applications. Includes tools like javac (compiler) and java (interpreter).
- JRE: Provides the runtime environment to execute Java programs.
java
Copy
public class HelloWorld {
public static void main(String[] args) {
System.out.println("Hello, World!");
}
}
- Explanation:
- public class HelloWorld: Defines a class named HelloWorld.
- public static void main(String[] args): The main method where execution begins.
- System.out.println("Hello, World!");: Prints "Hello, World!" to the console.
Introduction to Java programming.
2. Java Syntax and Data Types
- Primitive Data Types: int, double, char, boolean, etc.
- Reference Data Types: Objects, arrays, and strings.
Example:
java
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int age = 25;
double salary = 50000.50;
char grade = 'A';
boolean isJavaFun = true;
- Arithmetic Operators: +, -, *, /, %
- Comparison Operators: ==, !=, >, <
- Logical Operators: &&, ||, !
Example:
java
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int a = 10, b = 20;
if (a > b) {
System.out.println("a is greater");
} else {
System.out.println("b is greater");
}
- If-Else:
java
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int marks = 85;
if (marks >= 90) {
System.out.println("Grade A");
} else if (marks >= 80) {
System.out.println("Grade B");
} else {
System.out.println("Grade C");
}
- Loops:
java
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for (int i = 1; i <= 5; i++) {
System.out.println("Iteration: " + i);
}
Object-Oriented Programming (OOP) in Java
- Class: A blueprint for creating objects.
- Object: An instance of a class.
Example:
java
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class Car {
String color;
int speed;
void accelerate() {
speed += 10;
}
}
Car myCar = new Car();
myCar.color = "Red";
myCar.accelerate();
- Allows a class to inherit properties and methods from another class.
Example:
java
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class Vehicle {
void run() {
System.out.println("Vehicle is running");
}
}
class Bike extends Vehicle {
void accelerate() {
System.out.println("Bike is accelerating");
}
}
- The ability of a method to perform different tasks.
Example:
java
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class Animal {
void sound() {
System.out.println("Animal makes a sound");
}
}
class Dog extends Animal {
void sound() {
System.out.println("Dog barks");
}
}
Java Power Tools: Model software for teaching object-oriented design.
4. Arrays and Strings
-
Arrays store multiple values of the same type.
Example:
java
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int[] numbers = {1, 2, 3, 4, 5};
for (int num : numbers) {
System.out.println(num);
}
- Strings are immutable in Java.
Example:
java
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String name = "Java";
System.out.println(name.length()); // Output: 4
System.out.println(name.toUpperCase()); // Output: JAVA
5. Exception Handling
- Checked Exceptions: Compile-time exceptions (e.g., IOException).
- Unchecked Exceptions: Runtime exceptions (e.g., NullPointerException).
java
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try {
int result = 10 / 0;
} catch (ArithmeticException e) {
System.out.println("Cannot divide by zero");
}
Exception handling: A field study in java and. net.
6. File Handling in Java
java
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import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
public class FileExample {
public static void main(String[] args) {
try {
FileWriter writer = new FileWriter("example.txt");
writer.write("Hello, Java!");
writer.close();
} catch (IOException e) {
System.out.println("An error occurred.");
}
}
7. Case Study 1: Building a Student Management System
Create a program to manage student records, including adding, updating, and displaying student details.
- Use classes to represent students.
- Use arrays or collections to store student data.
java
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class Student {
String name;
int rollNo;
double marks;
Student(String name, int rollNo, double marks) {
this.name = name;
this.rollNo = rollNo;
this.marks = marks;
}
void display() {
System.out.println("Name: " + name + ", Roll No: " + rollNo + ", Marks: " + marks);
}
}
public class StudentManagement {
public static void main(String[] args) {
Student[] students = new Student[3];
students[0] = new Student("Alice", 1, 95.5);
students[1] = new Student("Bob", 2, 88.0);
students[2] = new Student("Charlie", 3, 91.0);
for (Student s : students) {
s.display();
}
}
}
- The program uses OOP principles to manage student data.
- Arrays store multiple student objects, and a loop displays their details.
8. Case Study 2: Creating a Banking Application
Develop a simple banking application to deposit, withdraw, and check balance.
- Use a class to represent a bank account.
- Implement methods for deposit, withdrawal, and balance inquiry.
java
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class BankAccount {
double balance;
BankAccount(double initialBalance) {
this.balance = initialBalance;
}
void deposit(double amount) {
balance += amount;
System.out.println("Deposited: " + amount);
}
void withdraw(double amount) {
if (amount > balance) {
System.out.println("Insufficient balance");
} else {
balance -= amount;
System.out.println("Withdrawn: " + amount);
}
}
void checkBalance() {
System.out.println("Balance: " + balance);
}
}
public class BankingApp {
public static void main(String[] args) {
BankAccount account = new BankAccount(1000);
account.deposit(500);
account.withdraw(200);
account.checkBalance();
}
}
- The program demonstrates encapsulation by keeping the balance private and providing methods to interact with it.
- It handles edge cases like insufficient balance during withdrawals.
Q&A Section
Question 1:
java
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public class Main {
public static void main(String[] args) {
int x = 5;
int y = x++;
System.out.println(y);
}
}
Options:
A) 5
B) 6
C) 0
D) Compilation Error
Explanation of Correct Answer:
- The x++ operator is a post-increment operator. This means the value of x is first assigned to y, and then x is incremented by 1.
- In this code:
- x is initially 5.
- y = x++ assigns the current value of x (which is 5) to y.
- After the assignment, x is incremented to 6, but y remains 5.
- Therefore, the output of System.out.println(y) is 5.
B) 6: This would be correct if the code used the pre-increment operator (++x). However, x++ increments x after the assignment, so y is not affected by the increment.
C) 0: There is no logical or syntactical reason for y to be 0. This option is incorrect.
D) Compilation Error: The code is syntactically correct and will compile without errors. This option is incorrect.
Question 2:
Options:
A) Platform Independence
B) Object-Oriented
C) Pointers
D) Multithreading
Correct Answer: C) Pointers
Explanation of Correct Answer:
- Java does not support pointers explicitly. Pointers are a feature of languages like C and C++, which allow direct memory manipulation. Java avoids pointers to ensure security and simplicity.
- Instead of pointers, Java uses references to interact with objects, which are safer and managed by the JVM.
A) Platform Independence: This is a core feature of Java. Java programs are compiled into bytecode, which can run on any device with a JVM, making it platform-independent.
B) Object-Oriented: Java is fundamentally object-oriented, meaning everything in Java is an object (except primitive data types).
D) Multithreading: Java supports multithreading, allowing concurrent execution of multiple threads within a program.
Question 3:
Options:
A) To create a constant variable
B) To allow a method or variable to belong to the class rather than an instance
C) To prevent a class from being instantiated
D) To make a variable thread-safe
Explanation of Correct Answer:
- The static keyword is used to define class-level methods and variables. These belong to the class itself rather than any specific instance of the class.
- For example:
- java
- Copy
class Counter {
static int count = 0; // Class-level variable
Counter() {
count++;
}
- }
Here, count is shared across all instances of the Counter class.
A) To create a constant variable: Constants are created using the final keyword, not static. For example: final int MAX_VALUE = 100;.
C) To prevent a class from being instantiated: This is achieved by making the class abstract or defining a private constructor, not by using static.
D) To make a variable thread-safe: The static keyword does not inherently make a variable thread-safe. Thread safety is achieved using synchronization or other concurrency mechanisms.
Question 4:
java
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public class Main {
public static void main(String[] args) {
String str1 = "Java";
String str2 = new String("Java");
System.out.println(str1 == str2);
}
}
Options:
A) true
B) false
C) Compilation Error
D) Runtime Error
Explanation of Correct Answer:
- In Java, the == operator checks for reference equality, not content equality.
- str1 is a string literal stored in the string pool, while str2 is a new object created in the heap memory.
- Even though both strings contain the same content ("Java"), they refer to different memory locations. Therefore, str1 == str2 evaluates to false.
A) true: This would be correct if the code used the .equals() method, which checks for content equality. For example: str1.equals(str2) would return true.
C) Compilation Error: The code is syntactically correct and will compile without errors.
D) Runtime Error: There is no runtime error in this code. It will execute and produce the output false.
Question 5:
Options:
A) Checked exceptions are checked at runtime.
B) Unchecked exceptions are checked at compile time.
C) Checked exceptions must be handled using try-catch or declared in the method signature.
D) Unchecked exceptions are always fatal and cannot be handled.
Explanation of Correct Answer:
- Checked exceptions are exceptions that are checked at compile time. Examples include IOException and SQLException.
- Java requires that checked exceptions either be:
- Caught using a try-catch block, or
- Declared in the method signature using the throws keyword.
A) Checked exceptions are checked at runtime: This is incorrect. Checked exceptions are checked at compile time, not runtime.
B) Unchecked exceptions are checked at compile time: This is incorrect. Unchecked exceptions (e.g., NullPointerException, ArithmeticException) are not checked at compile time. They occur at runtime.
D) Unchecked exceptions are always fatal and cannot be handled: This is incorrect. Unchecked exceptions can be handled using try-catch blocks, but they are not required to be handled.
Question 6:
java
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public class Main {
public static void main(String[] args) {
int[] numbers = {1, 2, 3, 4, 5};
System.out.println(numbers[5]);
}
}
Options:
A) 5
B) 0
C) ArrayIndexOutOfBoundsException
D) Compilation Error
Explanation of Correct Answer:
- Arrays in Java are zero-indexed, meaning the first element is at index 0.
- The array numbers have 5 elements, so the valid indices are 0 to 4.
- Accessing numbers[5] tries to access the 6th element, which does not exist. This results in an ArrayIndexOutOfBoundsException.
A) 5: This would be correct if the code accessed numbers[4], which is the last element of the array.
B) 0: There is no logical reason for the output to be 0. This option is incorrect.
D) Compilation Error: The code is syntactically correct and will compile without errors. The error occurs at runtime.
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